Elementary work during the rotation of a rigid body is equal to. The work of force during the rotation of a rigid body

Kinetic energy- the value is additive. Therefore, the kinetic energy of a body moving in an arbitrary way is equal to the sum of the kinetic energies of all P material points into which this body can be mentally divided: If the body rotates around a fixed axis z with an angular velocity of 1 m I 1 ...
(PHYSICS. MECHANICS)
  • Kinetic energy of a rotating rigid body
    The kinetic energy of a body moving in an arbitrary way is equal to the sum of the kinetic energies of all P material points (particles) into which this body can be mentally divided (Fig. 6.8) If the body rotates around the fixed axis Oz with angular velocity w, then the linear velocity of any /-th particle, ...
    (CLASSICAL AND RELATIVISTIC MECHANICS)
  • Rice. 6.4 Such a movement of the body, in which any two of its points (BUT and AT in fig. 6.4) remain stationary is called rotation around a fixed axis. It can be shown that in this case any point of the body that lies on the straight line connecting the points Aw W. Axis,...
    (THEORETICAL MECHANICS.)
  • Rotation of a body around a fixed axis
    Let the solid body in time sk made an infinitesimal rotation through the angle s/f relative to the fixed axis in the given frame of reference. This angle of rotation c/cp is a measure of the change in position of a body rotating about a fixed axis. By analogy with c/r, we will call c/f angular displacement....
    (PHYSICS: MECHANICS, ELECTRICITY AND MAGNETISM)
  • Analogy between translational and rotational motion
    This analogy was discussed above and follows from the similarity of the basic equations of translational and rotational motions. Just as acceleration is given by the time derivative of velocity and the second derivative of displacement, so is angular acceleration is given by the time derivative of the angular velocity and the second derivative of the angular displacement....
    (PHYSICS)
  • Translational and rotational motion
    Translational motion Translational motion is a motion solid body, at which any straight line drawn in this body moves, remaining parallel to its original position. The properties of translational motion are determined by the following theorem: in the translational motion of a body ...
    (APPLIED MECHANICS)
  • Consider a rigid body that can rotate around an axis of rotation fixed in space.

    Let's assume that F i is an external force applied to some elementary mass ∆m i rigid body and causing rotation. For a short period of time elementary mass will move to and therefore work will be done by the force

    where a is the angle between the direction of force and displacement. But equals F t are the projections of the force on the tangent to the trajectory of the mass movement , and the value . Hence

    It is easy to see that the product is the moment of force about a given axis of rotation z and acting on the body element D m i. Therefore, the work done by the force will be

    Summing up the work of the moments of forces applied to all elements of the body, we obtain for an elementarily small energy expended on an elementarily small rotation of the body d j:

    , (2.4.27)

    where is the resulting moment of all external forces acting on a rigid body with respect to a given axis of rotation z.

    Work for a finite period of time t

    . (2.4.28)

    Law of conservation of angular momentum and isotropy of space

    The law of conservation of angular momentum is a consequence of the basic law of the dynamics of rotational motion. In the system from P interacting particles (bodies) the vector sum of all internal forces, and hence the moments of forces, is equal to zero, and the differential equation of the moments has the form

    where the total angular momentum of the entire system is the resulting moment of external forces.

    If the system is closed

    whence it follows

    what is possible with

    Law of conservation of angular momentum: The angular momentum of a closed system of particles (bodies) remains constant.

    The law of conservation of angular momentum is a consequence of the property of the isotropy of space, which manifests itself in the fact that physical properties and the laws of motion of a closed system do not depend on the choice of the directions of the coordinate axes of inertial frames of reference.

    There are three physical quantities in a closed system: energy, momentum and angular momentum(which are functions of coordinates and velocities) are preserved. Such functions are called motion integrals. In the system from P there are 6 particles n–1 integrals of motion, but only three of them have the additivity property - energy, momentum and angular momentum.

    Gyroscopic effect

    A massive symmetrical body rotating at a high angular velocity around the axis of symmetry is called gyroscope.

    The gyroscope, being set in rotation, tends to keep the direction of its axis unchanged in space, which is a manifestation of law of conservation of angular momentum. The gyroscope is the more stable, the greater the angular velocity of rotation and the greater the moment of inertia of the gyroscope relative to the axis of rotation.

    If, however, a couple of forces are applied to a rotating gyroscope, tending to rotate it about an axis perpendicular to the axis of rotation of the gyroscope, then it will begin to rotate, but only around the third axis, perpendicular to the first two (Fig. 21). This effect is called gyroscopic effect. The resulting movement is called precessional movement or precession.

    Any body rotating around some axis precesses if it is acted upon by a moment of forces perpendicular to the axis of rotation.

    An example of precessional movement is the behavior of a children's toy called a spinning top or top. The Earth also precesses under the influence of the gravitational field of the Moon. The moment of forces acting on the Earth from the side of the Moon is determined by the geometric shape of the Earth - the absence of spherical symmetry, i.e. with her "flattenedness".

    Gyroscope*

    Let us consider the precessional movement in more detail. Such a movement is realized by a massive disk impaled on vertical the axis around which it rotates. The disc has an angular momentum directed along the axis of rotation of the disc (Fig. 22).

    At a gyroscope, the main element of which is a disk D, rotating at a speed around horizontal axes OO"there will be a torque about the point C and the angular momentum is directed along the axis of rotation of the disk D.

    The axis of the gyroscope is hinged at the point C. The device is equipped with a counterweight K. If the counterweight is installed so that the point C is the center of mass of the system ( m is the mass of the gyroscope; m 0 - counterweight mass To; the mass of the rod is negligible), then without friction we write:

    that is, the resulting moment of forces acting on the system is zero.

    Then the law of conservation of angular momentum is valid:

    In other words, in this case const; where J is the moment of inertia of the gyroscope, is the intrinsic angular velocity of the gyroscope.



    Since the moment of inertia of the disk about its axis of symmetry is a constant value, the angular velocity vector also remains constant both in magnitude and in direction.

    The vector is directed along the axis of rotation in accordance with the rule of the right screw. Thus, the axis of a free gyroscope keeps its position in space unchanged.

    If to counterbalance To add one more with mass m 1 , then the center of mass of the system will shift and a torque will appear relative to the point C. According to the moment equation, . Under the action of this torque, the angular momentum vector will receive an increment coinciding in direction with the vector:

    The gravity vectors and are directed vertically downwards. Therefore, the vectors , and , lie in the horizontal plane. After a while, the angular momentum of the gyroscope will change by a value and become equal to

    Thus, the vector changes its direction in space, all the time remaining in the horizontal plane. Taking into account that the gyroscope angular momentum vector is directed along the rotation axis, the rotation of the vector by some angle da during dt means to rotate the axis of rotation by the same angle. As a result, the axis of symmetry of the gyroscope will begin to rotate around a fixed vertical axis BB" with angular velocity:

    Such a movement is called regular precession, and the value is the angular velocity of precession. If at the initial moment the axis OO"The gyroscope is not installed horizontally, then during precession it will describe a cone in space relative to the vertical axis. The presence of friction forces leads to the fact that the angle of inclination of the gyroscope axis will constantly change. This movement is called nutation.

    Let us find out the dependence of the angular velocity of the gyroscope precession on the main parameters of the system. Let us project equality (123) onto the horizontal axis perpendicular to OO"

    From geometric considerations (see Fig. 22) at small angles of rotation , then , and the angular velocity of precession is expressed:

    This means that if a constant external force is applied to the gyroscope, then it will begin to rotate around the third axis, which does not coincide in direction with the main axis of rotation of the rotor.

    Precession, the magnitude of which is proportional to the magnitude operating force, holds the device oriented in the vertical direction, and the angle of inclination relative to the supporting surface can be measured. Once spun, a device tends to resist changes in its orientation due to angular momentum. This effect is also known in physics as gyroscopic inertia. In the event of termination of external influence, the precession ends instantly, but the rotor continues to rotate.

    The disk is acted upon by gravity, causing a moment of force about the fulcrum O. This moment is directed perpendicular to the axis of rotation of the disk and is equal to

    where l 0- distance from the center of gravity of the disk to the fulcrum O.

    Based on the basic law of the dynamics of rotational motion, the moment of force will cause in a time interval dt change in angular momentum

    The vectors and are directed along one straight line and are perpendicular to the axis of rotation.

    From fig. 22 shows that the end of the vector in time dt move to the corner

    Substituting into this relation the values L, dL and M, we get

    . (2.4.43)

    Thus, angular velocity of displacement of the end of the vector :

    and the upper end of the axis of rotation of the disk will describe a circle in the horizontal plane (Fig. 21). Such body movement is called precessional and the effect itself gyroscopic effect.


    DEFORMATIONS OF A SOLID BODY

    Real bodies are not absolutely elastic, therefore, when considering real problems, one has to take into account the possibility of changing their shape in the process of motion, i.e., take into account deformations. Deformation- this is a change in the shape and size of solid bodies under the influence of external forces.

    Plastic deformation- this is the deformation that persists in the body after the termination of the action of external forces. The deformation is called elastic, if, after the termination of the action of external forces, the body returns to its original size and shape.

    All types of deformations (tension, compression, bending, torsion, shear) can be reduced to simultaneously occurring tension (or compression) and shear deformations.

    Voltageσ - physical quantity, numerically equal to the elastic force per unit sectional area of ​​the body (measured in Pa):

    If the force is directed along the normal to the surface, then the stress normal, if - tangentially, then the voltage tangential.

    Relative deformation- a quantitative measure that characterizes the degree of deformation and is determined by the ratio of absolute deformation Δ x to the original value x characterizing the shape or size of the body: .

    - relative change in lengthl rod(longitudinal deformation) ε:

    - relative transverse tension (compression)ε', where d- rod diameter.

    Deformations ε and ε' always have different signs: ε' = −με where μ is a positive coefficient that depends on the properties of the material and is called Poisson's ratio.

    For small deformations, the relative deformation ε is proportional to the stress σ:

    where E- coefficient of proportionality (modulus of elasticity), numerically equal to the stress that occurs at a relative strain equal to unity.

    For the case of unilateral tension (compression), the modulus of elasticity is called Young's modulus. Young's modulus is measured in Pa.

    Having written down , we get - Hooke's law:

    elongation of a rod under elastic deformation is proportional to the force acting on the rod(here k- coefficient of elasticity). Hooke's law is valid only for small deformations.

    In contrast to the hardness factor k, which is a property of only the body, Young's modulus characterizes the properties of matter.

    For any body, starting from a certain value , the deformation ceases to be elastic, becoming plastic. Ductile materials are materials that do not collapse under stress significantly exceeding the elastic limit. Due to the property of plasticity, metals (aluminum, copper, steel) can be subjected to various mechanical processing: stamping, forging, bending, stretching. With a further increase in deformation, the material is destroyed.

    Tensile strength - the maximum stress that occurs in the body before its destruction.

    The difference in the limits of compressive and tensile strength is explained by the difference in the processes of interaction of molecules and atoms in solids during these processes.

    Young's modulus and Poisson's ratio fully characterize the elastic properties of an isotropic material. All other elastic constants can be expressed in terms of E and μ.

    Numerous experiments show that at small strains, the stress is directly proportional to the relative elongation ε (section OA diagrams) - Hooke's law is satisfied.

    The experiment shows that small deformations completely disappear after the load is removed (an elastic deformation is observed). For small deformations, Hooke's law is satisfied. The maximum voltage at which Hooke's law still holds is called limit of proportionality σ p. It corresponds to the point BUT diagrams.

    If you continue to increase the tensile load and exceed the proportional limit, then the deformation becomes non-linear (line ABCDEK). However, with small non-linear deformations, after the load is removed, the shape and dimensions of the body are practically restored (section AB graphic arts). The maximum stress at which there are no noticeable residual deformations is called elastic limit σ pack. It corresponds to the point AT diagrams. The elastic limit exceeds the proportional limit by no more than 0.33%. In most cases, they can be considered equal.

    If the external load is such that stresses arise in the body that exceed the elastic limit, then the nature of the deformation changes (section BCDEK). After the load is removed, the sample does not return to its previous dimensions, but remains deformed, although with a smaller elongation than under load (plastic deformation).

    Beyond the elastic limit at a certain stress value, point With diagrams, the elongation increases almost without increasing the load (section CD diagrams are almost horizontal). This phenomenon is called material flow.

    With a further increase in load, the voltage increases (from the point D), after which a narrowing (“neck”) appears in the least durable part of the sample. Due to the decrease in the cross-sectional area (point E) for further elongation, less stress is needed, but, in the end, the destruction of the sample occurs (point To). The maximum stress that a sample can withstand without breaking is called tensile strength - σ pc (it corresponds to the point E diagrams). Its value is highly dependent on the nature of the material and its processing.

    Consider shear deformation. To do this, we take a homogeneous body having the shape of a rectangular parallelepiped and apply to its opposite faces forces directed parallel to these faces. If the action of forces is uniformly distributed over the entire surface of the corresponding face S, then in any section parallel to these faces, a tangential stress will arise

    At small deformations, the volume of the body will practically not change, and the deformation consists in the fact that the "layers" of the parallelepiped are shifted relative to each other. Therefore, this deformation is called shear deformation.

    Under shear deformation, any straight line, initially perpendicular to the horizontal layers, will rotate through some angle . This will satisfy the relation

    ,

    where - shear modulus, which depends only on the material properties of the body.

    Shear deformation refers to homogeneous deformations, i.e., when all infinitesimal volume elements of the body are deformed the same.

    However, there are inhomogeneous deformations - bending and twisting.

    Let's take a homogeneous wire, fix its upper end, and apply a twisting force to the lower end, creating a torque M relative to the longitudinal axis of the wire. The wire will spin - each radius of its lower base will rotate around the longitudinal axis by an angle. This deformation is called torsion. Hooke's law for torsion deformation is written as

    where is a constant value for a given wire, called its torsion modulus. Unlike previous modules, it depends not only on the material, but also on the geometric dimensions of the wire.

    « Physics - Grade 10 "

    Why does the skater stretch along the axis of rotation to increase the angular velocity of rotation.
    Should a helicopter rotate when its propeller rotates?

    The questions asked suggest that if external forces do not act on the body or their action is compensated and one part of the body begins to rotate in one direction, then the other part must rotate in the other direction, just as when fuel is ejected from a rocket, the rocket itself moves in the opposite direction.


    moment of impulse.


    If we consider a rotating disk, it becomes obvious that the total momentum of the disk is zero, since any particle of the body corresponds to a particle moving with an equal speed in absolute value, but in the opposite direction (Fig. 6.9).

    But the disk is moving, the angular velocity of rotation of all particles is the same. However, it is clear that the farther the particle is from the axis of rotation, the greater its momentum. Therefore, for rotational motion it is necessary to introduce one more characteristic, similar to an impulse, - the angular momentum.

    The angular momentum of a particle moving in a circle is the product of the particle's momentum and the distance from it to the axis of rotation (Fig. 6.10):

    The linear and angular velocities are related by v = ωr, then

    All points of a rigid matter move relative to a fixed axis of rotation with the same angular velocity. A rigid body can be represented as a collection of material points.

    The angular momentum of a rigid body is equal to the product of the moment of inertia and the angular velocity of rotation:

    The angular momentum is a vector quantity, according to formula (6.3), the angular momentum is directed in the same way as the angular velocity.

    The basic equation of the dynamics of rotational motion in impulsive form.


    The angular acceleration of a body is equal to the change in angular velocity divided by the time interval during which this change occurred: Substitute this expression into the basic equation for the dynamics of rotational motion hence I(ω 2 - ω 1) = MΔt, or IΔω = MΔt.

    Thus,

    ∆L = M∆t. (6.4)

    The change in the angular momentum is equal to the product of the total moment of forces acting on the body or system and the time of action of these forces.

    Law of conservation of angular momentum:

    If the total moment of forces acting on a body or system of bodies with a fixed axis of rotation is equal to zero, then the change in the angular momentum is also equal to zero, i.e., the angular momentum of the system remains constant.

    ∆L=0, L=const.

    The change in the momentum of the system is equal to the total momentum of the forces acting on the system.

    The spinning skater spreads his arms out to the sides, thereby increasing the moment of inertia in order to decrease the angular velocity of rotation.

    The law of conservation of angular momentum can be demonstrated using the following experiment, called the "experiment with the Zhukovsky bench." A person stands on a bench with a vertical axis of rotation passing through its center. The man holds dumbbells in his hands. If the bench is made to rotate, then a person can change the speed of rotation by pressing the dumbbells to his chest or lowering his arms, and then spreading them apart. Spreading his arms, he increases the moment of inertia, and the angular velocity of rotation decreases (Fig. 6.11, a), lowering his hands, he reduces the moment of inertia, and the angular velocity of rotation of the bench increases (Fig. 6.11, b).

    A person can also make a bench rotate by walking along its edge. In this case, the bench will rotate in the opposite direction, since the total angular momentum must remain equal to zero.

    The principle of operation of devices called gyroscopes is based on the law of conservation of angular momentum. The main property of a gyroscope is the preservation of the direction of the axis of rotation, if external forces do not act on this axis. In the 19th century gyroscopes were used by navigators to navigate the sea.


    Kinetic energy of a rotating rigid body.


    The kinetic energy of a rotating solid body is equal to the sum of the kinetic energies of its individual particles. Let us divide the body into small elements, each of which can be considered a material point. Then the kinetic energy of the body is equal to the sum of the kinetic energies of the material points of which it consists:

    The angular velocity of rotation of all points of the body is the same, therefore,

    The value in brackets, as we already know, is the moment of inertia of the rigid body. Finally, the formula for the kinetic energy of a rigid body with a fixed axis of rotation has the form

    In the general case of motion of a rigid body, when the axis of rotation is free, its kinetic energy is equal to the sum of the energies of translational and rotational motions. So, the kinetic energy of a wheel, the mass of which is concentrated in the rim, rolling along the road at a constant speed, is equal to

    The table compares the formulas of the mechanics of the translational motion of a material point with similar formulas for the rotational motion of a rigid body.


    If a body is brought into rotation by a force, then its energy increases by the amount of work expended. As in translational motion, this work depends on the force and the displacement produced. However, the displacement is now angular and the expression for working when moving a material point is not applicable. Because the body is absolutely rigid, then the work of the force, although it is applied at a point, is equal to the work expended on turning the whole body.

    When turning through an angle, the point of application of the force travels a path. In this case, the work is equal to the product of the projection of the force on the direction of displacement by the magnitude of the displacement: ; From fig. it can be seen that is the arm of the force, and is the moment of the force.

    Then elementary work: . If , then .

    The work of rotation goes to increase the kinetic energy of the body

    ; Substituting , we get: or taking into account the equation of dynamics: , it is clear that , i.e. the same expression.

    6. Non-inertial frames of reference

    End of work -

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    Kinematics of translational motion

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    Consider an absolutely rigid body rotating around a fixed axis. If you mentally break this body into n mass points m 1 , m 2 , …, m n located at distances r 1 , r 2 , …, r n from the axis of rotation, then during rotation they will describe circles and move with different linear velocities v 1 , v 2 , …, v n. Since the body is absolutely rigid, the angular velocity of rotation of the points will be the same:

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    Taking into account the relationship between the angular and linear velocities, we get:

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    (4.10)



    where vc is the speed of the center of mass of the body; Jc- the moment of inertia of the body about the axis passing through its center of mass.
    Moment of force relative to the fixed axis z called a scalar Mz, equal to the projection onto this axis of the vector M moment of force defined relative to an arbitrary point 0 of the given axis. Torque value Mz does not depend on the choice of the position of point 0 on the axis z.
    If the axis z coincides with the direction of the vector M, then the moment of force is represented as a vector coinciding with the axis:

    Mz = [ RF]z
    Let's find an expression for work during the rotation of the body. Let the power F applied to point B, located at a distance from the axis of rotation r(Fig. 4.6); α is the angle between the force direction and the radius vector r. Since the body is absolutely rigid, the work of this force is equal to the work expended on turning the whole body.

    When the body rotates through an infinitesimal angle attachment point B passes the way ds = rdφ, and the work is equal to the product of the projection of the force on the direction of displacement by the magnitude of the displacement:

    dA = Fsinα*rdφ
    Given that Frsinα = Mz can be written dA = M z dφ, where Mz- the moment of force about the axis of rotation. Thus, the work during rotation of the body is equal to the product of the moment of the acting force and the angle of rotation.
    The work during rotation of the body goes to increase its kinetic energy:

    dA = dE k
    (4.11)

    Equation (4.11) is equation of the dynamics of rotational motion of a rigid body relative to a fixed axis.